A conducting ring with an area of 0.4 m2 and a resistance of 0.002 Ohm is placed in a uniform magnetic field

A conducting ring with an area of 0.4 m2 and a resistance of 0.002 Ohm is placed in a uniform magnetic field so that the plane of the ring is perpendicular to the field induction lines. What amount of heat is released in the ring in 0.2 s if the magnetic induction decreases at a rate of 0.08 T / s?

It is known that:
DB / dt = 0.08.
Then now we need a new formula:
E = d * B * S / dt.
Let’s transform the formula:
I = E / R = d * B * S / R * dt;
Let’s substitute and calculate:
I = 0.08 * 0.4 / 0.002;
I = 16 A;
Let’s write the formula:
Q = I ^ 2 * R * t;
Let’s find:
Q = 16 ^ 2 * 0.002 * 0.2;
Q = 0.1 J.
Answer: Q = 0.1 J.