A conductor 1.2 m long moves in a uniform magnetic field, the induction modulus of which is 0.10 T, perpendicular

A conductor 1.2 m long moves in a uniform magnetic field, the induction modulus of which is 0.10 T, perpendicular to the direction of the magnetic induction lines. The potential difference at the ends of the conductor is 0.24V. The module of the speed of movement of the conductor is

l = 1.2 m.

B = 0.1 T.

U = 0.24 V.

∠α = 90 °.

V -?

According to Faraday’s law of electromagnetic induction: U = ΔF / t = Δ (B * S * cos (90 ° – ∠α) / t.

cos (90 ° – 90 °) = cos0 ° = 1.

U = B * ΔS * / t, where ΔS is the change in the area that the conductor crosses during movement.

ΔS = l * Δd, where l is the length of the conductor, Δd is the distance the conductor has moved.

The speed of movement of the conductor V is expressed by the formula: V = Δd / t.

U = B * l * Δd / t = B * l * V.

V = U / B * l.

V = 0.24 V / 0.1 T * 1.2 m = 2 m / s.

Answer: in a magnetic field, the conductor moves at a speed of V = 2 m / s.