A conductor with a length of 25 cm and a resistance of 2.6 ohms is located in a uniform magnetic field with an induction of 20 mT. Determine the voltage applied to the conductor if a force of 0.04 N acts on it from the side of the magnetic field. The vector of magnetic induction makes an angle of 60 degrees with the conductor
L = 25cm = 0.25m.
R = 2.6 ohms.
B = 20 mT = 0.02 T.
Fa = 0.04 N.
∠α = 60 °.
We express the voltage at the ends of the conductor U from Ohm’s law for the section of the circuit: U = I * R, where I is the current in the conductor, R is the resistance of the conductor.
A conductor with a current in a magnetic field is acted upon by the Ampere force Fa, the value of which is determined by the formula: Fа = I * B * L * sinα, where I is the current in the conductor, B is the magnetic induction, L is the length of the conductor, ∠α is the angle between the direction of the current and the vector of magnetic induction B.
I = Fa / B * L * sinα.
The formula for determining the voltage U will take the form: U = Fа * R / B * L * sinα.
U = 0.04 N * 2.6 Ohm / 0.02 T * 0.25 m * sin60 ° = 24 V.
Answer: the voltage at the ends of the conductor is U = 24 V.
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