A conductor with a length of 30 cm is located horizontally. What value should the magnetic field induction have so that the gravity force of a conductor with a mass of 6 g is balanced by the Ampere force? A current of 5A flows through the conductor (take g = 10m / sq.s)?
L = 30cm = 0.3m.
m = 6 g = 0.006 kg.
g = 10 m / s2.
I = 5 A.
V – ?
According to 1 Newton’s law, the condition for the presence of a conductor at rest is the balancing of the forces that act on it.
The force of gravity Ft is balanced by the force of Ampere Famp: Ft = Famp.
The force of gravity Ft is determined by the formula: Ft = m * g.
Ampere force Famp is determined by the formula: Famp = I * B * L
m * g = I * B * L.
B = m * g / I * L.
B = 0.006 kg * 10 m / s2 / 5 A * 0.3 m = 0.04 T.
Answer: the magnetic induction of the field is B = 0.04 T.
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