A conductor with a length of L = 25 cm, located at an angle of 60 degrees to the direction of the magnetic
A conductor with a length of L = 25 cm, located at an angle of 60 degrees to the direction of the magnetic induction vector, is acted upon by a force of Amperes F = 0.2 H. The current in the conductor is I = 0.3 A. Make a problem using these data and solve it.
L = 25cm = 0.25m.
∠α = 60 °.
Famp = 0.2 N.
I = 0.3 A.
IN – ?
On a conductor with a current, in a magnetic field, the Ampere force Famp acts, the value of which is determined by the formula: Famp = I * B * L * sinα. Where I is the current in the conductor, B is the magnetic induction of the field, L is the length of the conductor, ∠α is the angle between the direction of the current and the vector of magnetic induction B.
The magnetic induction B of the field is expressed by the formula: B = Famp / I * L * sinα.
B = 0.2 N / 0.3 A * 0.25 m * sin60 ° = 3 T.
Answer: the conductor is in a magnetic field with induction B = 3 T.