A conductor with an active part length of 0.2 m, placed in a uniform magnetic field with an induction

A conductor with an active part length of 0.2 m, placed in a uniform magnetic field with an induction of 0.5 T, acts on a force of 0.8 N. Determine the current in the conductor, provided that it is perpendicular to the induction lines.

Given: L (length of the active part of the taken conductor) = 0.2 m; B (induction of a uniform magnetic field) = 0.5 T; Fa (Ampere acting force) = 0.8 N; by condition the active part of the conductor is located perpendicular to the lines of induction (α = 90º).

You can express the current strength in the active part of the conductor in question from the formula: Fa = I * B * l * sinα, whence I = Fa / (B * l * sinα).

Calculation: I = 0.8 / (0.5 * 0.2 * sin 90º) = 8 A.

Answer: A current of 8 A flows through the active part of the conductor.