A copper ball weighing 26.7N floats in the water. Half of the ball protrudes above the water surface.

A copper ball weighing 26.7N floats in the water. Half of the ball protrudes above the water surface. Find the volume of the ball.

If the body floats in water, then the force of Archimedes is equal to its weight. Archimedes’ strength is determined from the formula:
F = V * ρ * g,
Where
V is the volume of water displaced by the body,
ρ = 1000kg / m ^ 3 – water density,
g = 10m / s ^ 2 – acceleration of gravity,
F = 26.7H;
V = F / (ρ * g) = 26.7 / (10 * 1000) = 26.7 * 10 ^ (- 4) m ^ 3 = 2670cm ^ 3;
Since the ball is only half submerged in water, its volume is twice as large: 5340 cm ^ 3.