A copper piece weighing 7.1 kg was completely immersed in a tank filled to the brim with kerosene.
| September 19, 2021 | education
A copper piece weighing 7.1 kg was completely immersed in a tank filled to the brim with kerosene. Find the weight of the spilled kerosene.
Initial data: m (mass of a copper part) = 7.1 kg.
Reference values: ρк (kerosene density) = 800 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2; ρm (copper density) = 8900 kg / m3.
The weight of the spilled kerosene (the force of Archimedes, which acts on the copper part) is determined by the formula: P = Fa = ρк * g * V = ρк * g * m / ρм.
Calculation: P = 800 * 10 * 7.1 / 8900 = 6.382 N ≈ 6.4 N.
Answer: C. The weight of the spilled kerosene is 6.4 N.
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