A copper saucepan weighing 300 g holds 1 liter of water. How much heat is needed to heat water

A copper saucepan weighing 300 g holds 1 liter of water. How much heat is needed to heat water from 15 to 100 ° C in this saucepan?

Given: m1 (weight of the pan) = 300 g (in SI m1 = 0.3 kg); V (volume of water) = 1 l (in SI V = 1 * 10-3 m3); t0 (initial temperature) = 15 ºС; t (final temperature) = 100 ºС.

Constants: ρw (water density) = 1000 kg / m3; Cw (specific heat capacity of water) = 4200 J / (kg * K); Cm (specific heat capacity of copper) = 400 J / (kg * K).

Heat costs: Q = Q1 + Q2 = Cw * ρw * V * (t – t0) + Cm * m1 * (t – t0) = (Cw * ρw * V + Cm * m1) * (t – t0).

Calculation: Q = (4200 * 1000 * 1 * 10-3 + 400 * 0.3) * (100 – 15) = 367 200 J.