A crane with an area of 20 cm2 was installed in the oil tank at a depth of 5 m.

A crane with an area of 20 cm2 was installed in the oil tank at a depth of 5 m. With what force the oil presses on the tap, if the oil density is 800 kg / m3.

h = 5 m.

g = 10 m / s2.

S = 20 cm2 = 0.002 m2.

ρ = 800 kg / m3.

F -?

The force F with which the oil presses on the valve can be expressed by the formula: F = P * S, where P is the oil pressure, S is the area of the valve.

The hydrostatic pressure of oil P at the bottom of the tank is expressed by the formula: P = ρ * g * h, where ρ is the oil density, g is the gravitational acceleration, h is the depth at which the valve is installed in the tank.

F = ρ * g * h * S.

F = 5 m * 10 m / s2 * 0.002 m2 * 800 kg / m3 = 80 N.

Answer: oil presses on the valve with a force of F = 80 N.