A cube with a side of 3 cm was cut into cubes with a side of 1 cm and a turret with a base

A cube with a side of 3 cm was cut into cubes with a side of 1 cm and a turret with a base in one cube was folded from them. What is the surface area of the resulting tower?

1. According to the problem statement, a cube with a side of 3 cm was cut into cubes with a side of 1 cm.

In total, it turned out 3 * 3 * 3 = 27 cubes measuring 1 cm * 1 cm.

2. It is known that a turret was made of them with a base in one cube.

We got a rectangle with 6 edges.

Since the height of the rectangle consists of 27 cubes, it means that it is 27 cm.

Then the area of each of the four faces is 27 * 1 = 27 cm2.

3. The area of two more faces (upper and lower) will be equal to 1 * 1 = 1 cm2.

4. Let’s calculate the surface area.

S = 4 * 27 + 1 + 1 = 108 + 2 = 110 cm2.

Answer: The surface area of the tower is 110 cm2.



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