A cube with a side of 3 cm was cut into cubes with a side of 1 cm and a turret with a base
A cube with a side of 3 cm was cut into cubes with a side of 1 cm and a turret with a base in one cube was folded from them. What is the surface area of the resulting tower?
1. According to the problem statement, a cube with a side of 3 cm was cut into cubes with a side of 1 cm.
In total, it turned out 3 * 3 * 3 = 27 cubes measuring 1 cm * 1 cm.
2. It is known that a turret was made of them with a base in one cube.
We got a rectangle with 6 edges.
Since the height of the rectangle consists of 27 cubes, it means that it is 27 cm.
Then the area of each of the four faces is 27 * 1 = 27 cm2.
3. The area of two more faces (upper and lower) will be equal to 1 * 1 = 1 cm2.
4. Let’s calculate the surface area.
S = 4 * 27 + 1 + 1 = 108 + 2 = 110 cm2.
Answer: The surface area of the tower is 110 cm2.