A cubic aluminum bar with a rib length of 10 cm has cooled down from 70 degrees

A cubic aluminum bar with a rib length of 10 cm has cooled down from 70 degrees Celsius to 30 degrees Celsius. How much heat was released during this?

Bar volume:

V = a ^ 3 = 0.1 ^ 3 m3 = 0.001 m3 (a is the length of the edge of the cube).

Bar weight:

m = ρV = 2712 kg / m3 * 0.001 m3 = 2.712 kg (ρ is density).

The amount of heat released:

Q = cm (t1 – t0), where c is the specific heat capacity of aluminum, (t1 – t0) is the temperature difference (the temperature difference on the Kelvin scale coincides with the temperature difference on the Celsius scale).

Q = 897 J / kg K * 2.712 kg * (70 ° C – 30 ° C) = 97306.56 J = 96.3 KJ.

Answer: 96.3 KJ.



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