A current of 10 A flows through an insulated ring conductor with a radius of 20 cm. Two long wires with currents

A current of 10 A flows through an insulated ring conductor with a radius of 20 cm. Two long wires with currents of 10 and 20 A pass perpendicular to the plane of the ring so that they touch the ring at points lying on opposite ends of the diameter. Determine the induction in the center of the ring when currents flow in the same or opposite directions.

Let’s designate I = 10, the current in the ring conductor; I = 10, I = 20 currents in straight conductors. Then:
H = 10 / (2 * 0.2) = 25 – magnetic field strength of the ring conductor in the center of the ring;
H = 10 / (2P * 0.2) = 25 / P – magnetic field strength of the first straight conductor in the center of the ring;
H = 20 / (2P * 0.2) = 50 / P – magnetic field strength of the second straight conductor in the center of the ring.
If currents in straight conductors flow in one direction, then the strength of the resulting magnetic field in the center of the ring is:
H = 25 ^ 2 + (25 / P) ^ 2 = 26.2;
If the currents in straight conductors flow in opposite directions, then the strength of the resulting magnetic field in the center of the ring is:
H = 25 ^ 2 + (75 / P) ^ 2 = 34.6;
Answer: H = 26.2; H = 34.6.