A current of 10 A was passed for 20 minutes through a copper sulfate solution at a copper anode.

A current of 10 A was passed for 20 minutes through a copper sulfate solution at a copper anode. How many grams has decreased the weight of the anode?

The condition provides an electrolytic bath with an anode. When an electric current passes through this system, the copper anode dissolves and its mass decreases. To determine the loss of mass, we use Faraday’s law: m = k * I * t. Let’s find the electrochemical equivalent of copper by dividing its atomic mass by the number of electrons donated and the Faraday number.

k = 64/2 * 26.8 = 1.194 g / A * h

Let’s convert time into hours by dividing by 60: t = 20/60 = 0.333 hours.

Then the mass of the copper anode will decrease by:

m = 1.194 g / A * h * 10 A * 0.333 h = 3.98 grams.