A current of 100 mA flows to a 5 H coil. What is the magnetic field energy of the coil?

the magnetic field energy of the coil is calculated by the formula W = Li ^ 2/2
Substitute these values and calculate: W = 5 * 0.1 ^ 2/2 = 0.025 or 25 * 10 ^ (- 3) J or 25 mJ
Answer: 25 mJ

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