A current of 1000 A flows through two parallel buses 20 m long and in the air at a distance of 0.4 m. Determine the forces acting on the tires.
Initial data: Δl (length of parallel buses) = 20 m; d (distance at which the tires are in the air) = 0.4 m; I (bus current) = I1 = I2 = 1000 A.
Reference values: km (proportional factor) = 2 * 10 ^ -7 N / A2.
The force of interaction of parallel buses is determined by the formula: Fa = km * I1 * I2 * Δl / d = km * I ^ 2 * Δl / d.
Let’s make the calculation: Fa = 2 * 10 ^ -7 * 1000 ^ 2 * 20 / 0.4 = 10 N.
Answer: Tires are attracted to each other with a force of 10 N.
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