A current of 3 A flows through the circuit section, consisting of two parallel-connected resistors with resistances

A current of 3 A flows through the circuit section, consisting of two parallel-connected resistors with resistances of 2 and 3 Ohms. Determine the voltages at the ends of the circuit section?

Given:

R1 = 2 Ohm – the value of the first resistance;

R2 = 3 Ohm – the value of the second resistance;

I = 3 Amperes – the strength of the current passing through the section of the electrical circuit.

It is required to determine U (Volt) – the voltage at the ends of the circuit section.

Since the condition of the problem indicates that the resistors are connected in parallel, we find the total resistance of the circuit section:

1 / R = 1 / R1 + 1 / R2;

1 / R = (R1 + R2) / (R1 * R2);

R = R1 * R2 / (R1 + R2) = 2 * 3 / (2 + 3) = 6/5 = 1.2 ohms.

Then the voltage will be equal to:

U = I * R;

U = 3 * 1.2 = 3.6 Volts.

Answer: the voltage at the ends of the circuit section is 3.6 volts.