A current of 4 amperes flows through a conductor 12 meters long and with a cross-section of 0.1 mm

| May 22, 2021 | education

A current of 4 amperes flows through a conductor 12 meters long and with a cross-section of 0.1 mm squared under a voltage of 220 V. determine the resistivity of the conductor.

Let us derive the formula for the resistivity of the conductor.

Knowing that R = (ρ * L) / S, we find ρ = R * S / L, where S = the cross-sectional area of the conductor, L is the length of the conductor, R is the electrical resistance of the conductor, which we find by the formula R = U / I, U – voltage, I – current strength.

Thus, substituting the value of the electrical resistance of the conductor into the original formula for calculating the resistivity of the conductor, we get:

ρ = (U * S) / (L * I) = (U * S) / (L * I) = (220 (V) * 0.1 (mm ^ 2)) / (12 (m) * 4 (A) ) = 11/24 (Ohm * mm2 / m).



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