A current of 5.2 A is passed through the magnesium sulfate solution for 18 minutes. What substances are released

A current of 5.2 A is passed through the magnesium sulfate solution for 18 minutes. What substances are released on the electrodes and in what volumes? Give a complete diagram of the salt electrolysis process

Given:
MgSO4
I = 5.2 A
t = 18 min = 1080 s

To find:
V (substances) -?

Solution:
1) MgSO4
К (-): 2H2O + 2e -> H2 ↑ + 2OH (-)
А (+): 2H2O – 4е -> O2 ↑ + 4H (+)
2H2O => 2H2 + O2;
2) n (H2) = (I * t) / (F * z) = (5.2 * 1080) / (96500 * 2) = 0.03 mol;
3) V (H2) = n (H2) * Vm = 0.03 * 22.4 = 0.672 l;
4) n (O2) = (I * t) / (F * z) = (5.2 * 1080) / (96500 * 4) = 0.015 mol;
5) V (O2) = n (O2) * Vm = 0.015 * 22.4 = 0.336 l.

Answer: At the cathode, H2 will be released with a volume of 0.672 liters; at the anode – O2 with a volume of 0.336 liters.