A cyclist and a car travel along the road in one direction at a speed of 15 and 65 km / h

A cyclist and a car travel along the road in one direction at a speed of 15 and 65 km / h relative. The car is catching up with the cyclist. How fast are they converging?

Since the vector of the speed of movement of the cyclist and the vector of the speed of the car are directed in the same direction, we calculate the relative speed of their approach by the formula:

V (1,2) = V2 – V1, where V2 is the speed of the vehicle (V2 = 65 km / h), V1 is the speed of the cyclist (V1 = 15 m / s).

V (1,2) = V2 – V1 = 65 – 15 = 50 m / s.

Answer: The car approaches the cyclist at a speed of 50 m / s.