A cyclist left point A, and after 1 hour 30 minutes, a second cyclist followed him along the same road, whose speed was

| December 27, 2020 | education

A cyclist left point A, and after 1 hour 30 minutes, a second cyclist followed him along the same road, whose speed was 6 km / h higher than the speed of the first, and 4 hours 30 minutes after his departure he overtook the first by 3 km. Find the speed of the first cyclist.

1. We translate time in minutes into hours:
1 hour 30 minutes = 1.5 hours.
4 hours 30 minutes = 4.5 hours.
2. We take the speed of the first cyclist as x, the second cyclist was riding at the speed
(x + 6) km / h.
3. The first cyclist left the settlement earlier than the second and was on the way
1.5 + 4.5 hours = 6 hours.
4. Let’s make the equation:
4.5 (x + 6) – 6x = 3;
4.5 x + 27 – 6x = 3;
– 1.5 = – 24;
x = 16 km / h.
Answer: the speed of the first cyclist is 16 km / h.



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