A cyclist left the village for the city at a speed of 250m / min, after 10 minutes a bus departed at a speed of 750m / min

A cyclist left the village for the city at a speed of 250m / min, after 10 minutes a bus departed at a speed of 750m / min. After how long the bus will catch up with the cyclist. At what distance from the village will the meeting take place. What is the distance between the cyclist and the bus 8 minutes after the meeting.

In 10 minutes, a cyclist riding at a speed of 250 m / min will have time to cover (10 min) * (250 m / min) = 2500 m.
After the bus leaves, the distance between the cyclist and the bus will decrease at a speed of: 250 m / min + 750 m / min = 1000 m / min.
The bus will catch up with the cyclist in: (2500 m) / (1000 m / min) = 2.5 min.
The meeting will take place at a distance: (2.5 min) * (750 m / min) = 1875 m from the village.
8 minutes after the meeting, the distance between them will be: (8 min) * (1000 m / min) = 8 km.
Answer: 1875 m; 8 kilometers.



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