A cyclist left town A to B at a speed of 15.5 km / h. After 2 hours, another cyclist left B to meet

A cyclist left town A to B at a speed of 15.5 km / h. After 2 hours, another cyclist left B to meet him at a speed of 13.5 km / h. How many hours after leaving A and at what distance from A will they meet if 0.5 of the distance between A and B is 44.5 km?

1. We calculate the distance between cities:

44.5 x 2 = 89 kilometers.

2. Accepted for x time after the cyclist leaves city A, after which he will meet with another cyclist.

3. Let’s compose the equation:

15.5x + 13.5 (x + 2) = 89;

29x = 116;

x = 4 hours.

6. The meeting of cyclists will take place at a distance of 15.5 x 4 = 62 kilometers from the city A.

Answer: the meeting of cyclists will take place 4 hours after the cyclist leaves town A, at a distance of 62 kilometers from it.