A cyclist rushes along a suspension bridge over a ravine at a constant speed V = 18 km / h V = 18 km / h
A cyclist rushes along a suspension bridge over a ravine at a constant speed V = 18 km / h V = 18 km / h. Considering the bridge as an arc of a circle with a radius of R = 50 m R = 50 m, determine the weight of the bicycle together with the cyclist in the central, lowest part of the bridge. Express your answer in NN, rounded to the nearest whole number. The mass of the cyclist is M = 65 kg M = 65 kg, the mass of the bicycle is m = 15 kg m = 15 kg. Free fall acceleration g = 10 m / s2 g = 10 m / s2.
Given: V (constant speed of the cyclist on the suspension bridge) = 18 km / h = 5 m / s; R (radius of the suspension (concave) bridge) = 50 m; m1 (cyclist’s weight) = 65 kg; m2 (bike weight) = 15 kg.
Constants: g (acceleration due to gravity) = 10 m / s2.
The weight of the cyclist together with the bike at the bottom of the suspension bridge is determined by the formula: P = m * a + N = m * an + m * g = m * (an + g) = (m1 + m2) * (V ^ 2 / R + g).
Calculation: P = (65 + 15) * (5 ^ 2/50 + 10) = 80 * (0.5 + 10) = 80 * 10.5 = 840 N.