A cylinder filled with gas under a pressure of 2.84 MPa was in the warehouse at a temperature of 7 ° C.

| July 13, 2021 | education

A cylinder filled with gas under a pressure of 2.84 MPa was in the warehouse at a temperature of 7 ° C. After half of the gas was consumed, the cylinder was brought into the room. What is the temperature in the room if the gas pressure in the cylinder after a while becomes 1.52 MPa?

To determine the value of the temperature in the room, we will use the equations: Rn * V = mn * R * Tn / M and Pk * V = mk * R * Tk / M, from where we can express: R / (M * V) = Rn / (mn * Tn) = Pk / (mk * Tk) and Tk = Pk * mn * Tn / (mk * Rn).

Variables: Рк – final pressure (Рк = 1.52 MPa); mн (initial gas mass) = 2mк (final gas mass); Tн – temperature in the warehouse (Тн = 280 К = 7 ºС); Рн – initial pressure (Рн = 2.84 MPa).

Calculation: Tk = Pk * mn * Tn / (mk * Rn) = 1.52 * 2mk * 280 / (mk * 2.84) = 299.72 K (26.72 ºС).

Answer: The room temperature is 26.72 ºС.



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