Let’s draw a segment OB, the length of which is equal to the radius of the sphere. OB = R.
From the right-angled triangle OO1B, by the Pythagorean theorem, we determine the length of the leg OO1.
OO1 ^ 2 = OB ^ 2 – BO1 ^ 2 = R ^ 2 – r ^ 2.
The segment OO1 is half the length of the height of the inscribed cylinder, then AB ^ 2 = 2 * OO1 = 2 * (R ^ 2 – r ^ 2).
AB = √ (2 * (R ^ 2 – r ^ 2)) see.
Determine the area of the base of the cylinder.
Sop = n * r ^ 2.
Determine the volume of the cylinder
V = Sax * AB = n * r ^ 2 * √ (2 * (R ^ 2 – r ^ 2)) cm3.
Answer: The volume of the cylinder is n * r ^ 2 * √ (2 * (R ^ 2 – r ^ 2)) cm3.
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