A cylinder with a volume of 0.5 • 10-3 m 3 contains 2 kg of oxygen O2 at a

| September 14, 2021 | education

A cylinder with a volume of 0.5 • 10-3 m 3 contains 2 kg of oxygen O2 at a temperature of 15 degrees. Determine the gas pressure in the cylinder.

To calculate the value of the oxygen pressure in the indicated cylinder, it is necessary to use the Mendeleev-Clapeyron equation: P = m * R * T / (V * MO2).

Constants and variables: m is the mass of oxygen contained in the indicated cylinder (m = 2 kg); R – universal gas constant (R = 8.31 J / (K * mol)); Т – temperature (Т = 15 ºС = 288 К); V is the volume of the cylinder (V = 0.5 * 10 ^ -3 m3); MO2 is the molar mass of oxygen (MO2 = 3.2 * 10 ^ -2 kg / mol).

Calculation: P = m * R * T / (V * MO2) = 2 * 8.31 * 288 / (0.5 * 10 ^ -3 * 3.2 * 10 ^ -2) = 299.16 * 10 ^ 6 Pa.

Answer: The oxygen in the indicated cylinder is under a pressure of 299.16 MPa.



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