A cylinder with a volume of V = 6 · 10-2 m3 contains oxygen at a temperature of t = 270C.

| July 5, 2021 | education

A cylinder with a volume of V = 6 · 10-2 m3 contains oxygen at a temperature of t = 270C. Determine the mass of oxygen consumed if the pressure in the cylinder has decreased by ΔP = 100 kPa. The process is considered to be isothermal.

V = 6 * 10 ^ -2 m ^ 3.

T = 543 K.

ΔP = 100 kPa = 100 * 10 ^ 3 Pa.

M (O2) = 0.032 kg / mol.

R = 8.31 m ^ 2 * kg / s ^ 2 * K * mol.

T = const.

Δm -?

Let us write the Mendeleev-Cliperon equation: P * V = m * R * T / M, where

Let us express the mass of the gas: m = M * P * V / R * T.

m1 = M * P1 * V / R * T.

m2 = M * P2 * V / R * T.

Δm = M * P1 * V / R * T – M * P2 * V / R * T = M * V * (P1 -P2) / R * T = M * V * ΔP / R * T.

Δm = 0.032 kg / mol * 6 * 10 ^ -2 m ^ 3 * 100 * 10 ^ 3 Pa / 8.31 m ^ 2 * kg / s ^ 2 * K * mol * 543 K = 0.04255 kg.

Answer: oxygen consumed Δm = 0.04255 kg.



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