A dark-haired brown-eyed woman is heterozygous in 1 avenue, married a fair-haired brown-eyed

A dark-haired brown-eyed woman is heterozygous in 1 avenue, married a fair-haired brown-eyed man heterozygous in 2 alleys. Define the genotypes and phenotypes of children?

Let’s designate the gene that causes the development of dark hair as B, then the gene for light hair will be b.

Let’s designate the gene that determines the development of brown eyes as C, then the gene for light eyes will be c.

A dark-haired brown-eyed woman is, by condition, a heterozygote for the hair color gene. Let’s write it BbCC. It will produce two types of eggs: BC and bC.

A fair-haired brown-eyed man will be homozygous for the hair color gene, otherwise the trait would not be realized in his phenotype, for the eye color gene he is heterozygous according to the condition of the problem. Let’s write it as bbСс, the spermatozoa produced by it – bС and bс.

Children who may be born to this couple will look like this:

dark-haired children with brown eyes (BbCC, BbCc) – 50%;

children with blond hair and brown eyes (bbCC, bbCc) – 50%;