A deformed spring with a rigidity of 40 N / m sets the body in motion. How deformed was it if the
| August 6, 2021 | education
A deformed spring with a rigidity of 40 N / m sets the body in motion. How deformed was it if the kinetic energy of the body reached 50 J?
Initial data: k (stiffness of the deformed spring) = 40 N / m; Ek (kinetic energy that the body reached after the action of the spring) = 50 J.
The deformation of the spring is determined from the formula: Ek = Ep (potential energy of the deformed spring) = k * Δx2 / 2, whence Δx ^ 2 = 2Ek / k and Δx = √ (2Ek / k).
Calculation: Δx = √ (2 * 50/40) = 1.58 m.
Answer: The spring was deformed by 1.58 meters.
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