A diameter and a chord equal to the radius are drawn from the point of this circle. Find the angle between them.

By condition, the chord AB is equal to the radius of the circle, OA = AB.

Draw a radius from the center of the circle to point B of the chord.

The resulting triangle is equilateral, since OA = AB = OB = R.

In an equilateral triangle, all angles are 60.

Answer: The angle OAB is 60.



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