A diesel locomotive weighing 100 tons moves with an acceleration of 0.5 m / s2.

A diesel locomotive weighing 100 tons moves with an acceleration of 0.5 m / s2. Find the traction force of the locomotive if the friction coefficient is 0.006.

To find the magnitude of the traction force of the used diesel locomotive, we project all the forces onto the horizontal axis: m * a = Ftyag – Ftr = Ftyag – μ * m * g, whence Ftyag = m * a + μ * m * g = (a + μ * g) * m.

Constants and variables: a – acceleration of the locomotive (a = 0.5 m / s2); μ – coefficient of friction (μ = 0.006); g – acceleration due to gravity (g ≈ 10 m / s2); m is the mass of the locomotive (m = 100 t = 100 * 10 ^ 3 kg).

Let’s perform the calculation: Ftyag = (a + μ * g) * m = (0.5 + 0.006 * 10) * 100 * 10 ^ 3 = 56 * 10 ^ 3 = 56 kN.

Answer: The locomotive is moving under the influence of a traction force of 56 kN.