A diesel locomotive with a capacity of 294 kW carries a train weighing 1000 tons.

A diesel locomotive with a capacity of 294 kW carries a train weighing 1000 tons. The coefficient of friction on the horizontal section of the track is 0.003. How fast does the train travel?

To find out the speed of the specified diesel locomotive (we consider it constant, Ftr = Fthrust), we use the formula: N = F * V, whence we express: V = N / F = N / Ftr = N / (μ * m * g).

Const: g – acceleration due to gravity (g ≈ 9.8 m / s2).

Data: N – power of the specified locomotive (N = 294 kW = 294 * 10 ^ 3 W); m is the mass of the train (m = 1000 t = 10 ^ 6 kg); μ – coeff. friction (μ = 0.003).

Let’s calculate: V = N / (μ * m * g) = 294 * 10 ^ 3 / (0.003 * 10 ^ 6 * 9.8) = 10 m / s.

Answer: The specified locomotive must move at a speed of 10 m / s.