A diver in a rigid spacesuit can dive to a depth of 300 m to determine the water pressure at this depth.

h = 300 m;

ρ = 1000 kg / m3;

g = 9.8 N / kg;

R – ?

To calculate the pressure of a liquid (water), we use the formula: p = gρh, where p is the water pressure, g is the acceleration of gravity (constant equal to 9.8 N / kg), ρ is the density of water, h is the depth.

Plug in the known values and calculate.

p = 9.8 N / kg * 1000 kg / m3 * 300 m = 2940000 Pa = 2940 kPa.

Answer: the water pressure at a depth of 300 m is 2940 kPa.