A diver in a rigid spacesuit dives into the water to a depth of 250m. determine the water pressure

A diver in a rigid spacesuit dives into the water to a depth of 250m. determine the water pressure in the sea at this depth (density of seawater 1030 kg / m3)

To find the magnitude of the seawater pressure at the indicated depth, we apply the formula: P = ρmw * g * h.

Data: ρmw – density of seawater (according to the condition ρmw = 1030 kg / m3); g – acceleration of gravity (g = 9.81 m / s2); h – depth (h = 250 m).

Let’s make a calculation: P = ρmv * g * h = 1030 * 9.81 * 250 ≈ 2.53 * 10 ^ 6 Pa.

Answer: Sea water at the indicated depth creates a pressure equal to 2.53 MPa.