A droplet weighing 1 mg is in equilibrium in a uniform electric field with a strength of 50 N / C

A droplet weighing 1 mg is in equilibrium in a uniform electric field with a strength of 50 N / C. Determine the droplet charge.

Since the droplet under consideration is in equilibrium, the equality will be true: E * q (force from the side of the field) = m * g (gravity), whence we express: q = m * g / E.

Const: q – acceleration due to gravity (q ≈ 10 m / s2).

Data: m – droplet mass (m = 1 mg = 10-6 kg); E – tension (E = 50 N / C).

Calculation: q = m * g / E = 10-6 * 10/50 = 0.2 * 10-6 C = 200 nC.

Answer: The charge of the droplet under consideration is 200 nC.