A droplet weighing 1 mg is in equilibrium in a uniform electric field with a strength of 50 N / cell
| July 26, 2021 | education
A droplet weighing 1 mg is in equilibrium in a uniform electric field with a strength of 50 N / cell. Determine the charge of the droplet.
E = 50 N / Cl.
m = 1 g = 0.001 kg.
g = 9.8 m / s2.
q -?
According to 1 Newton’s law, the condition for the equilibrium of a droplet is the compensation of all forces that act on it.
The droplet is acted upon by the force of gravity Ft, directed vertically downward, and the force of the electric field Fe, directed vertically upward.
Ft = Fe.
Let us express the electrostatic force: Fe = q * E.
The force of gravity Ft is determined by the formula: Ft = m * g.
q * E = m * g.
q = m * g / E.
q = 0.001 kg * 9.8 m / s2 / 50 N / C = 0.0002 Cl.
Answer: the droplet has an electric charge q = 0.0002 C.
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