A droplet with a mass of 10 ^ -4 g is in equilibrium in a uniform electric field with a strength

A droplet with a mass of 10 ^ -4 g is in equilibrium in a uniform electric field with a strength of 98N / CL. Determine the amount of charge of the droplet.

To find out the magnitude of the charge of the specified droplet, consider the equality: E * qk = F (effective force) = mk * g, whence we express: qk = mk * g / E.

Const: g – acceleration due to gravity (g ≈ 9.8 m / s2).

Data: mk – the mass of the specified droplet (mk = 10-4 g; in the SI system mk = 10-7 kg); E – known electric field strength (E = 98 N / C).

Let’s perform the calculation: qk = mk * g / E = 10-7 * 9.8 / 98 = 10-8 Cl.

Answer: The charge of the indicated droplet should be 10 nC.