A dynamometer with a spring of 12.5 N / m is attached to a trolley weighing 0.1 kg.

A dynamometer with a spring of 12.5 N / m is attached to a trolley weighing 0.1 kg. What acceleration will the trolley receive when the spring is stretched by 4 cm?

To find out the acceleration that the trolley should acquire, consider the equality: mt * a = Fel (elastic force) = k * Δx, from where we express: a = k * Δx / mt.

Data: k is the stiffness of the dynamometer spring (k = 12.5 N / m); Δx – tension, deformation of the spring (Δx = 4 cm, in SI system Δx = 4 * 10-2 m); mt is the mass of the bogie (mt = 0.1 kg).

Let’s perform the calculation: a = k * Δx / mt = 12.5 * 4 * 10-2 / 0.1 = 5 m / s2.

Answer: The cart must acquire an acceleration of 5 m / s2.