A flat body floats on the surface of the water. Find the volume of the body if its mass is 70 kg

A flat body floats on the surface of the water. Find the volume of the body if its mass is 70 kg, and the volume of the body part above the water is 7 dm ^ 3.

Initial data: m (body weight) = 70 kg; V1 (volume of the body part above water) = 7 dm ^ 3 = 0.007 m ^ 3.

Constants: ρ (density of water, we assume that the body is floating in fresh water) = 1000 kg / m ^ 3.

Since the body is at rest, the action of gravity is compensated by the buoyancy force of Archimedes: Ft = Fа.

m * g = ρ * g * V2.

m = ρ * V2.

V2 (volume of the underwater part of the body) = m / ρ = 70/1000 = 0.07 m ^ 3.

Body volume: V = V1 + V2 = 0.007 + 0.07 = 0.077 m ^ 3.

Answer: The volume of the body is 0.077 m ^ 3.



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