A flat capacitor consists of two plates located in parallel in the air, each with an area of 100
A flat capacitor consists of two plates located in parallel in the air, each with an area of 100 cm2, the distance between them is 0.2 cm, determine the capacitance of the capacitor.
We calculate the electrical capacity of a flat capacitor by the formula:
С = ε * ε0 * S / D, where ε is the relative permittivity of the dielectric (ε = 1 (air)), ε0 is the electrical constant (ε0 = 8.85 * 10 ^ -12 F / m), S is the area of the plates capacitor (S = 100 cm ^ 2 = 100 * 10 ^ -4 m ^ 2), D – dielectric thickness (D = 0.2 cm = 0.2 * 10 ^ -2 m).
Let’s calculate the electrical capacity:
С = ε * ε0 * S / D = 1 * (8.85 * 10 ^ -12) * (100 * 10 ^ -4) / (0.2 * 10 ^ -2) = 4425 * 10 ^ -14 = 44.25 * 10 ^ -12 = 44.25 pF.
Answer: The capacitance of the capacitor is 44.25 pF.