A flat capacitor with a capacity of 500pF is charged with a charge of 2 * 10 ^ (- 6) Cl.
| July 13, 2021 | education
A flat capacitor with a capacity of 500pF is charged with a charge of 2 * 10 ^ (- 6) Cl. Determine the voltage across the capacitor plates.
The capacitance of a capacitor can be calculated using the formula:
C = q / U, where C is the capacitance of the capacitor (500 pF = 500 * 10 ^ -12 F), q is the electric charge (q = 2 * 10 ^ -6 C), U is the voltage across the capacitor plates (V).
Let us express and calculate the voltage across the capacitor plates:
U = q / C = (2 * 10 ^ -6) / (500 * 10 ^ -12) = 4000 V = 4 kV.
Answer: The voltage across the capacitor plates is 4 kV.
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