A flat ice floe floats in fresh water. determine the smallest area of the ice floe on which a person weighing

A flat ice floe floats in fresh water. determine the smallest area of the ice floe on which a person weighing m = 75 kg can hold if its thickness is h = 30 cm

We know from the condition that a flat ice floe floats in fresh water. And we need to find the smallest area of the ice floe on which a person weighing m = 75 kg can hold, if its thickness is h = 30 cm = 0.3 m.
First of all, we calculate the maximum pressure that an ice floe can withstand according to the formula:
p = p * g * h = 0.3 m * 10 N / kg * 1,000 N / kg = 3,000 Pa.
Let’s apply the formula to calculate the pressure in terms of the force per area ratio:
p = F / S;
Let us express the area:
S = F / p.
We find the strength as:
F = m * g.
Substitute and calculate:
S = mg / p = (75 kg * 10 N / kg) / 3000 Pa = 0.25 m ^ 2 = 2500 cm ^ 2.