A force equal to 160 Newtons was applied to the spring and stretched by 3 cm.
| October 8, 2021 | education
A force equal to 160 Newtons was applied to the spring and stretched by 3 cm. Determine the coefficient of stiffness of the spring
Initial data: F (force applied to the spring) = 160 N, x (amount of tension of the spring) = 3 cm.
SI system: x = 3 cm = 0.03 m.
The force applied to the spring will be balanced by the elastic force, which can be calculated by the formula:
F = F = k * x and k = F / x.
Let’s perform the calculation:
k = 160 / 0.03 = 5333 N / m.
Answer: The coefficient of stiffness of this spring is 5333 N / m.
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