A force equal to 3N acts on the lever, what is the moment of this force if the shoulder is 15 cm?

Given:

F = 3 Newton – the magnitude of the force acting on the lever;

dx = 15 centimeters – force shoulder F.

It is required to determine p (N * m) – the moment of this force.

We will convert the units of measurement of length to the SI system:

dx = 15 cm = 15 * 10-2 = 15/100 = 0.15 meters.

Then, the moment of force will be equal to:

p = F * dx = 3 * 0.15 = 0.45 N * m (newton per meter).

Answer: the moment of force 3 Newton with a shoulder of 15 centimeters will be equal to 0.45 N * m