A force of 10 N must be applied to compress the spring by 2 cm. Determine the energy

A force of 10 N must be applied to compress the spring by 2 cm. Determine the energy of elastic deformation when the spring is compressed by 4 cm from the non-deformed state.

Data: Δx1 (initial spring deformation) = 2 cm (0.02 m); F (force required to initially compress the spring) = 10 N; Δx2 (required spring compression) = 4 cm (0.04 m).

1) Calculate the stiffness of the spring under consideration: k = F / Δx1 = 10 / 0.02 = 500 N / m.

2) Determine the energy of elastic deformation when the spring is compressed by 4 cm: En = 0.5 * k * Δx22 = 0.5 * 500 * 0.042 = 0.4 J.

Answer: The energy of elastic deformation is 0.4 J.