A force of 10n stretches the spring by 2cm. what is the force that stretches this spring 7cm?
| September 23, 2021 | education
Initial data: F1 (the first tensile force of the spring) = 10 N; Δx1 (first tension of the spring) = 2 cm; Δx2 (second spring tension) = 7 cm.
Since one and also a spring is stretched (the spring stiffness is constant), then the second tensile force is determined from the equality: F1 / Δх1 = F2 / Δх2, whence F2 = F1 * Δх2 / Δх1.
Calculation: F2 = 10 * 7/2 = 35 N.
Answer: A force of 35 N will stretch the spring by 7 cm.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
