A force of 12 N was applied to the right arm of the lever, which force is applied to the left arm if its length is 0.3 m

univerkov | December 4, 2020 | education

A force of 12 N was applied to the right arm of the lever, which force is applied to the left arm if its length is 0.3 m and the length of the right arm is 0.5 m.

M1 = M2
M1 = F1e1
M2 = F2e2
F1e1 = F2e2
12 * 0.5 = 0.3 * F2
F2 = (12 * 0.5) /0.3=20H

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