A force of 124 N began to act on a body weighing 31 kg. What is the speed of the body 22 s

A force of 124 N began to act on a body weighing 31 kg. What is the speed of the body 22 s after the start of movement?

1) Determine the acceleration with which the body began to move using Newton’s second law: F = m * a, where, according to the condition, F is the force that began to act on the body (F = 124 N), m is the mass of the body (m = 31 kg).

a = F / m = 124/31 = 4 m / s ^ 2.

2) Let us determine the speed of the body 22 s after the start of the movement:

V = V0 + a * t, we consider that the body began to move from a state of rest (V0 = 0 m / s).

V = 0 + a * t = 4 * 22 = 88 m / s.

Answer: The speed of the body will be equal to 88 m / s.



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