A force of 200 N acts on the left arm of the lever, and a load weighing 8 kg is suspended to the right arm.

| September 11, 2021 | education

A force of 200 N acts on the left arm of the lever, and a load weighing 8 kg is suspended to the right arm. The left arm of the lever is 7 cm. What is the right arm of the lever if it is in equilibrium? 2) Under what condition can bodies of different masses 2 and 10 kg have the same potential energy?

1) Given: Fl = 200 N; mpr = 8 kg; g ≈ 10 m / s2; Ll = 7 cm (0.07 m); the lever is in balance.

Calculation formula: Fl * Ll = Fpr * Lpr, whence Lpr = Fl * Ll / Fpr = Fl * Ll / (mpr * g) = 200 * 0.07 / (8 * 10) = 0.175 m (17.5 cm) …

2) Given: m1 = 2 kg; m2 = 10 kg; g ≈ 10 m / s2.

Calculation formula: En1 = En2; m1 * g * h1 = m2 * g * h2; m1 * h1 = m2 * h2; 2 * h1 = 10 * h2, whence h1 = 5h2. The bodies will have the same potential energy if the first body is 5 times higher than the second.



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